What is the sprayer application rate in gallons per acre if 25.6 fluid ounces of water is collected in 30 seconds from an individual nozzle?

What is the sprayer application rate in gallons per acre if 25.6 fluid ounces of water is collected in 30 seconds from an individual nozzle?

• A. 15 gal/acre
• B. 17 gal/acre
• C. 20 gal/acre
• D. 12 gal/acre

Answer: (B)

To determine the sprayer application rate in gallons per acre, we first need to convert the collected fluid ounces to gallons and then adjust for the time it takes for the collection. Starting with the given information, we know that 25.6 fluid ounces of water is collected in 30 seconds. Since there are 128 fluid ounces in a gallon, we calculate the volume in gallons: \[ 25.6 \text{ fluid ounces} \div 128 \text{ fluid ounces/gallon} = 0.2 \text{ gallons} \] Next, we need to calculate how many gallons would be applied in one acre based on the application field's width and the speed of application. Typically, sprayer nozzles have a specific output associated with their configuration (e.g., gallons per minute, or GPM). To find the application rate per minute, we can extrapolate from the 30 seconds of collection. Since there are 60 seconds in a minute: \[ 0.2 \text{ gallons in 30 seconds} \times 2 = 0.4 \text{ gallons per minute} \] Next, to find out how much volume is applied per acre, we have to consider how many minutes it

To determine the sprayer application rate in gallons per acre, we first need to convert the collected fluid ounces to gallons and then adjust for the time it takes for the collection.

Starting with the given information, we know that 25.6 fluid ounces of water is collected in 30 seconds. Since there are 128 fluid ounces in a gallon, we calculate the volume in gallons:

[

25.6 \text{ fluid ounces} \div 128 \text{ fluid ounces/gallon} = 0.2 \text{ gallons}

]

Next, we need to calculate how many gallons would be applied in one acre based on the application field's width and the speed of application. Typically, sprayer nozzles have a specific output associated with their configuration (e.g., gallons per minute, or GPM).

To find the application rate per minute, we can extrapolate from the 30 seconds of collection. Since there are 60 seconds in a minute:

[

0.2 \text{ gallons in 30 seconds} \times 2 = 0.4 \text{ gallons per minute}

]

Next, to find out how much volume is applied per acre, we have to consider how many minutes it